On 21/08/18 12:16, Jacob Braig wrote: > I am just starting out coding and decided on python.
It looks like you are using Python v2 (maybe v2.7?) but the latest version is 3.7 and for beginners we normally recommend adopting v3. It doesn't change anything much in this case but it saves you relearning too much later if you decide to switch. > python better but the code I have now keeps popping up an error Always include the full error text so we don't need to guess. It contains a lot of useful information. > AMMO = " This is how much ammo remains for .40 pistol %s. " > > print "Program has started." > > ammopistol = raw_input("Enter total ammo before use. ") raw_input() does what it says, it reads the raw characters typed at the keyboard. It does not try to guess what they are - in this case numbers - it just stores them as a character string. You need to convert them to the type of data you need. ammopistol = int( raw_input("Enter total ammo before use. ") ) > ammopused = raw_input("Enter total ammo used. ") same here > ammopleft = ammopistol - ammopused You cannot subtract character strings so you got an error, but once you convert the data it should work. > print AMMO % (ammopistol, ammopused,) ammoleft This won't work however. Your AMMO string has one % placeholder in it so it expects exactly 1 value on the right of the % sign. You are providing a tuple of two values. Then you add a third value that's not in the tuple and is invalid syntax in Python. Python won't know what to do and you will get another error. You really want something like print AMMO % ammoleft HTH -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor