nathan tech wrote:
> Hi there,
>
> So I am running over some coding ideas in my head for creating a map for
> a game.
>
> This map would expand based on how far the user explores.
>
> I figure there are two ways to do this:
>
> 1: the list method:
>
> map=[]
>
> for x in range(3):
>
> temp=[]
>
> for y in range(3):
>
> temp.append(default_grid_format)
>
> map.append(temp)
>
>
> then when ever the user explores a square not on the current map, it
> would do this:
>
> for x in range(len(map)):
>
> map[x].append(default_grid_format)
>
> temp=[]
>
> for x in range(len(map[0])):
>
> temp.append(default_grid_format)
>
> map.append(temp)
>
> Obviously, though, this creates a lot of data for squares that are still
> ultimately unexplored.
>
> So here was my other idea:
>
>
> 2. the dictionary method:
>
> map={}
>
> for x in range(3):
>
> for y in range(3):
>
> key=str(x)+":"+str(y)
>
> map[key]=default_grid_format
>
>
> Then when user explores new square do:
>
> key=str(player_x)+":"+str(player_y)
>
> map[key]=default_grid_format
>
>
> Is this an efficient method compared to 1?
>
> Is it, code wise, sound logic?
>
>
>
> I guess I'm just looking for a second opinion from experienced peoples.
>
> thanks everyone.
Forget about "efficiency", try to write clean code.
For the above samples this means
- no unused data
- no unnecessary stringification
If you base your code on a defaultdict cells spring into existence as
needed:
$ cat tmp.py
from collections import defaultdict
def get_default_format():
return "whatever"
def show_cell(x, y):
print(f"x = {x}, y = {y}, format = {grid_formats[x,y]!r}")
grid_formats = defaultdict(get_default_format)
grid_formats[42, 42] = "this cell is special"
player_location = 3, 4
show_cell(*player_location)
show_cell(42, 42)
$ python3.6 tmp.py
x = 3, y = 4, format = 'whatever'
x = 42, y = 42, format = 'this cell is special'
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
