Albert ARIBAUD <albert.u.b...@aribaud.net> writes:

> Hi Måns,
>
> On Tue, 11 Feb 2014 15:33:09 +0000, Måns Rullgård <m...@mansr.com>
> wrote:
>
>> The problem is that the current settings do
>> the exact opposite.  By using -munaligned-access by default, you are
>> asking the compiler to go ahead and do whatever it thinks is best, which
>> is sometimes to perform an intentional unaligned access.  Exactly when
>> this will happen is largely impossible to predict.
>
> The -munaligned-access option does *not* "[ask] the compiler to go
> ahead and do whatever it thinks is best", it tells it to use direct
> native accesses when unaligned accesses are required, as opposed to
> splitting unaligned accesses into smaller but aligned aligned native
> accesses, which is what you get with -mno-unaligned-access.

The flag does both of those things.  It even gives the compiler
permission to merge multiple adjacent accesses into a single wider one.

>> To get the behaviour you desire, the code should be compiled with
>> -mno-unaligned-access.  This tells the compiler to _never_ automatically
>> perform an unaligned memory access.  If it thinks an address might be
>> unaligned, it will split the access.
>
> This shows that you really have not read my argument, in which I *did*
> explain why we tell the compiler *not* to split unaligned accesses into
> smaller correctly aligned accesses, i.e., why -munaligned-access is
> used.

I have read what you call your argument.  Unfortunately for you, it is
based on false premises, and as such any conclusions you arrive at are
incorrect.

-- 
Måns Rullgård
m...@mansr.com
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