Hello, Le 14/01/2011 23:39, Tom Warren a écrit :
> So instead of, say uart->lcr = 0, you'd prefer writel(0, uart->lcr), > where writel = __arch_putl(v, a) = (*(volatile unsigned int *)(a) = > (v))? > Is that different enough from 'uart->lcr = 0' to warrant the change? > Does it add some HW barriers or forced read-before-write that the > 'volatile' struct doesn't? writel() and readl() do not introduce "read-before-write", that is, they do not perform any more than what their names imply, but yes they do introduce barriers, or more precisely, they force the compiler to do so. Amicalement, -- Albert. _______________________________________________ U-Boot mailing list U-Boot@lists.denx.de http://lists.denx.de/mailman/listinfo/u-boot
