Ed,

        Copy the file and then resize it. That way you can confirm that you
have the same information. I had this problem a long time ago and was able
to read the records. 

Kathleeni

-----Original Message-----
From: Burwell, Ed [mailto:[EMAIL PROTECTED] 
Sent: Friday, November 02, 2007 8:11 AM
To: u2-users@listserver.u2ug.org
Subject: RE: [U2] [UD] Possible causes of corrupt data on a UniData static
file


Kathleene,

I wish it were that easy.  READNEXT and READ can't get it's hands on these
records.

-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Kathleeni M Hunter
Sent: Thursday, November 01, 2007 6:34 PM
To: u2-users@listserver.u2ug.org
Subject: RE: [U2] [UD] Possible causes of corrupt data on a UniData static
file


Basic program read record, check id for char (o), if there get new id, write
record with new id and delete old record.

-----Original Message-----
From: Wally Terhune [mailto:[EMAIL PROTECTED] 
Sent: Thursday, November 01, 2007 2:14 PM
To: u2-users@listserver.u2ug.org
Subject: Re: [U2] [UD] Possible causes of corrupt data on a UniData static
file


I wrote previously:
UniBasic does not prevent you from writing out a record or ID with char(0)
imbedded. It is a legal character. No guesses as to the cause of your
particular issue. To assist in diagnosis, you can search your problem file
for all occurances of char(0) in data records or keys using an option on
'guide'. For instance:

guide -U0 PROBLEM.FILE.NAME

option is -U followed by the ascii charcter number you want to search for.

I should add that the information about characters found is in
GUIDE_ERRORS.LIS.

For instance:
guide -U65 VOC                 (looking for 'A')

pg GUIDE_ERRORS.LIS
VOC
  File Integrity:
    Group 0, block 1, record number 0 = "COL.SPACES"
     has char(65) in key.
    Group 0, block 1, record number 1 = "LIST.LABEL"
     has char(65) in key.
    Group 0, block 1, record number 7 = "STATS"
     has char(65) in key.
    Group 0, block 1, record number 0 = "COL.SPACES"
     record has char(65) in data.
    Group 0, block 1, record number 1 = "LIST.LABEL"
     record has char(65) in data.
...  (many more entries)
                                                                           
 Wally Terhune                                                             
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