Fawaz, >I have a Unidata numeric field >(Amount- 100.00 or -100.00) and I need to convert it >to a 8 Bite integer so that Informix will recognise >it.
Do you mean 8bit or 8byte? For an 8 bit integer you need to output CHAR(n) where n is a number between 0 and 255. For an 8 byte (64 bit) integer you would need to do something like this. I aplogise if this isn't correct UD code, I usually work on UV. I am assuming that the output integer is in MSB order and that the bits of each byte are in MSb order. ININT = 1145689 GOSUB MAKE8BYTE STOP MAKE8BYTE: * Initialise output as 0 OUTINT = STR(CHAR(0), 8) FOR I = 1 TO 8 * Get lowest 8bits LOWESTBYTE = BITAND(ININT, 255) * Convert this to a byte representation and place it in the output integer OUTINT[8-I, 1] = CHAR(LOWESTBYTE) * Remove the lowest byte 8bits from the integer ININT = INT(ININT/256) NEXT I RETURN HTH, Craig -- u2-users mailing list [EMAIL PROTECTED] http://www.oliver.com/mailman/listinfo/u2-users