It worked!
Thanks a lot!
---
Doug
2008/11/19 Gray Norton <[EMAIL PROTECTED]>
> In general, it's best to avoid synchronous ajax requests.
>
> You can invoke functions from within your callback, but you'll need to
> change the way you're doing it, because JavaScript's "this" variable in your
> example below isn't referring to the object you want -- it's referring
> instead to the object literal being passed to jQuery.ajax.
>
> You have a couple of options: A) If the function you're calling is only
> used in the context of this callback, you can move the functionality
> directly into the callback function itself; or B) If that's not an option
> because the function also needs to be called from elsewhere, you'll need to
> refer to the function in a way that doesn't rely on using "this" from within
> the callback. For example:
>
> var myObj = this;
>
> jQuery.ajax({
> ...
> success: function() {
> myObj.myFunction();
> ...
> }
>
> or
>
> var myFunction = this.function;
>
> jQuery.ajax({
> ...
> success: function() {
> myFunction();
> ...
> }
>
> Hope this helps.
>
> - Gray
>
>
> On Wed, Nov 19, 2008 at 10:17 AM, Douglas Nogueira <
> [EMAIL PROTECTED]> wrote:
>
>> How can i change the network call to sync? There is others consequences of
>> this change?
>>
>> When you say: "So, all the work you want to do, must be done inside your
>> callback
>> function..."
>> I cant do that. I cant call any function from the inside of my callback
>> function. Doesnt work!
>> Like this:
>>
>> jQuery.ajax({
>> type: "get",
>> url: url,
>> data: params,
>> dataType: "text",
>> success: function(response) {
>> this.myfunction();
>> }
>> });
>>
>>
>> 2008/11/18 Fernando Takai <[EMAIL PROTECTED]>
>>
>>
>>> Douglas,
>>>
>>> That's because success function is an async callback -- it runs just
>>> after the network call.
>>> When you use a callback you don't have access to the this pointer, since
>>> you are not inside your own object.
>>>
>>> It works like this
>>>
>>> aux = 0
>>> network call (after this call returns, i will call your callback)
>>> displayMessage
>>> network call returned, displayMessage
>>>
>>> So, all the work you want to do, must be done inside your callback
>>> function - or, change the async to sync.
>>>
>>> Cheers.
>>>
>>> On 11/18/08 5:22 PM, Douglas Nogueira wrote:
>>> > I have this:
>>> >
>>> > aux=0;
>>> >
>>> > jQuery.ajax({
>>> > type: "get",
>>> > url: url,
>>> > data: params,
>>> > dataType: "text",
>>> > error: function(msg) {
>>> > alert("problem");
>>> > },
>>> > success: function(response) {
>>> > if(response)
>>> > if(response==1){
>>> > aux=response;
>>> > displayMessage(aux); /_(1)_/
>>> > }
>>> > }
>>> > });
>>> >
>>> > displayMessage(aux); _/(2)/_
>>> >
>>> >
>>> > When i do the first displayMessage(aux) he shows 1, but when i do the
>>> > second he shows 0.
>>> > And i cant call any function inside of my sucess function...
>>> > What can i do to set the aux=1 if the response=1??
>>> >
>>> > -----
>>> > Doug
>>> >
>>> > >
>>>
>>> --
>>> Fernando "Takai"
>>> http://flickr.com/photos/supeertakai
>>> http://fernandotakai.jaiku.com
>>>
>>> Get Ubiquity: https://wiki.mozilla.org/Labs/Ubiquity/
>>>
>>>
>>>
>>>
>>
>>
>
> >
>
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