Hi Samuel, I understand your problem, but I think bash is working the way it's documentation says it should. The bash manual page says:
"? Expands to the status of the most recently executed foreground pipeline." and "The return status of a pipeline is the exit status of the last command, unless the pipefail option is enabled." The last command isn't the command farthest to the right -- it's the last command to exit. In your example, > local BAR="$(false)" the shell expands $(false) before it runs the local built-in, so the last command is local. Since local succeeded at lexically scoping your variable, it returns true and completes the pipeline with a true value. If you agree with this assessment, can you please close the bug? Thank you, -Dave -- local assignment clobbers the return code https://bugs.launchpad.net/bugs/304114 You received this bug notification because you are a member of Ubuntu Bugs, which is subscribed to Ubuntu. -- ubuntu-bugs mailing list ubuntu-bugs@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-bugs
