This also breaks the following script: target='\1.o' echo foo.c | sed -e 's/\([a-z]*\).c/'$target'/'
Ubuntu /bin/dash: $ target='\1.o' $ set -x $ echo foo.c | sed -e 's/\([a-z]*\).c/'$target'/' + echo foo.c + sed -e s/\([a-z]*\).c/1.o/ 1.o Ubuntu /bin/bash: $ target='\1.o' $ set -x $ echo foo.c | sed -e 's/\([a-z]*\).c/'$target'/' + sed -e 's/\([a-z]*\).c/\1.o/' + echo foo.c foo.o HP-UX /bin/sh $ target='\1.o' $ set -x $ echo foo.c | sed -e 's/\([a-z]*\).c/'$target'/' + echo foo.c + sed -e s/\([a-z]*\).c/\1.o/ foo.o As you can see, sed is called without the backslash in the replacement command when dash is used: sed ... /1.o/ instead of the expected sed ... /\1.o/ -- Wrong escape character processing in dash https://bugs.launchpad.net/bugs/268929 You received this bug notification because you are a member of Ubuntu Bugs, which is subscribed to Ubuntu. -- ubuntu-bugs mailing list ubuntu-bugs@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-bugs
