Jan,

you asked if that was correct - that depends on what you did, exactly.
This is incorrect:

$ SHOTWELL_LOG=1
$ shotwell

If you want a UNIX shell to pass a variable to a command, you need to do
either of these:

$ SHOTWELL_LOG=1 shotwell

or

$ export SHOTWELL_LOG=1
$ shotwell

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https://bugs.launchpad.net/bugs/709516

Title:
  Shotwell import hangs always at the same point?!

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