Make sense, I introduced this change.

There is another similar puzzle that says:

If p < x < q and r < y < s. Which of the following options makes x < y
true?

a) s > p (correct)

b) p < r

c) p > r

d) q = s

If the variable s is bigger than p then the condition x < y is always
true.</_rationale>

Do you see any problem on it?

Thanks a lot,

Jordi,

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https://bugs.launchpad.net/bugs/785721

Title:
  Invalid logical question

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