Paul Brunt wrote:
> Hi,
>
> I'm not 100% sure but this would make sense as the first answer to me:
> the machine with 990 ticks should be experiencing time at
> (990/1000) of real time
> the machine with 1015 ticks should be experiencing time at
> (1015/1000) of real time
> The length of time it would take the two systems to go out of sync be 
> 5 seconds would be:
> (1015/1000)a - (990/1000)a = 5
> where "a" is the time needed between syncs
> so answer is 200 seconds
>
> Sorry, but the I've not really got time to work out the second one 
> right now. I'll try and get back to it at some point if someone hasn't 
> beaten me to it ;-)
>
> Thanks
>
> Paul

Paul,

I was in the middle of typing mine when yours came in, so as far as I'm 
concerned, you've won, particularly given we came up with the same 
answer  :-)

However, I'll claim the prize for part 2 :-)

M.

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