On 6/4/07, Dominic Forrest <[EMAIL PROTECTED]> wrote: > > Hi, > I need to regularly convert a few hundred/thousand .jpgs to a mpeg4 > (or other) video. These files are selected as the result of a mysql > query from perl and sit within a number of directories along with many > more images which will not form part of the video - hence I cannot use > wildcards with ffmpeg (or any other tool). I can easily list all the > filenames in order to a file but am unable to find a way to use this > file (which currently has the full path to one jpg on each line) as > input to ffmpeg. > > Currently the only way I have found to do this is to copy all the files > (or create links) to a new directory which then allows me to use > wildcards - however this seems horribly inefficient! > > Any thoughts or solutions welcomed! > > > Dom > > -- > ubuntu-uk@lists.ubuntu.com > https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk > https://wiki.kubuntu.org/UKTeam/ >
Hi Dom. You could use $(cat file). A quick example should illustrate this for you: [EMAIL PROTECTED]:~$ echo "one" > file1 [EMAIL PROTECTED]:~$ echo "two" > file2 [EMAIL PROTECTED]:~$ echo -e "file1\nfile2" > files [EMAIL PROTECTED]:~$ cat $(cat files) one two [EMAIL PROTECTED]:~$ Dump your mysql output to a file, and then use $(cat file) in place of where your wildcard/files would be. Any good? :-) Kris -- ubuntu-uk@lists.ubuntu.com https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk https://wiki.kubuntu.org/UKTeam/
