Hi Eugene,
Just a couple of questions before I start to reproduce you problem.
1/ Are you sure that it is not able to find beans implementing
IApplication? Obviously you will
get exactly the same exception if it finds more than one bean,
right?
2/ Which version of Spring are you using?
And you are saying that the whole story works using the development
runner, right?
Have a nice day. Regards,
christian
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On Jul 24, 2009, at 6:49 AM, Eugene Coelho wrote:
Hi,
For a past few days i have been trying to get ulc springmvc
integration working for a project. I could manage to get
development runner running as shown in one of the mails on the
mailing list .
The problem arises when i access the application as a webapplication.
When i access the jsp page the SpringWebULCApplication gets
instantiated but when it goes to find the application using the
following
public static IApplication getApplication(ApplicationContext
context, String applicationBeanName) {
IApplication application;
if(applicationBeanName != null) {
application = ((IApplication)
context.getBean(applicationBeanName));
} else {
final Map applications =
context.getBeansOfType(IApplication.class);
if(applications.size() != 1) throw new
IllegalArgumentException("Application context must contain exactly
one ULCApplication: "+applications);
application = (IApplication)
applications.values().iterator().next();
}
return application;
}
it is not able to locate the bean which implements
IApplication.class and hence terminates with an error "Application
context must contain exactly one ULCApplication:"
Can someone help me in making use of SpringWebULCApplication class.
Is there anything more that is required like an
applicationContext.xml file to let the framework find the class that
implements IApplication.class ?
------------------------------------------------------------------------
So far i have managed to do the following changes.
1>Edit web.xml to introduce
<servlet>
<servlet-name>springapp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</
servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springapp</servlet-name>
<url-pattern>/ulc</url-pattern>
</servlet-mapping>
2>Introduce file called springapp-servlet.xml in the same location
as web.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-
beans-2.5.xsd">
<!-- the application context definition for the springapp
DispatcherServlet -->
<bean name="/ulc" class="org.mernst.ulcjava.spring.ULCController"/>
<bean class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping
"/>
</beans>
3>Edit the xxxx.jsp file and update the url to access /ulc
<%
String applicationUrl = request.getScheme() + "://" +
request.getServerName() + ":" + request.getServerPort() +
request.getContextPath() + "/ulc";
%>
4>Introduce spring.xml in the resources ( i guess this would be only
used with development launcher code)
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.springframework.org/schema/
beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
">
<bean name="ABC" scope="prototype"
class="com.xxx.xxxx.application.ABC">
</bean>
</beans>
(Class ABC implements IApplication)
5>Development Runner Code
public class SpringDevelopmentRunner implements IApplication {
private static final String SPRING_XML = "/spring.xml";
private static final String SPRING_IAPPLICATION_BEAN = "ABC";
private ClassPathXmlApplicationContext _springContext;
private IApplication _delegate;
public void start() {
_springContext = new ClassPathXmlApplicationContext(SPRING_XML);
_delegate = (IApplication)
_springContext.getBean(SPRING_IAPPLICATION_BEAN);
_delegate.start();
}
...
.. ...
Thanks,
Eugene
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