Dominikus Scherkl <Dominikus dot Scherkl at glueckkanja dot com> wrote:
> utf16high = 0xD7C0 + (utf32 >> 10); > utf16low = 0xDC00 + (utf32 & 1023); > > this is very easy to invert: > > utf32 = ((utf16high - 0xD7C0) <<10) + (utf16low & 1023); This is good, but I'd write hexadecimal 0x3FF instead of decimal 1023, as it shows the purpose of the bitmask a little more clearly. (Apologies to Karl Pentzlin, if he is still on this list.) -Doug Ewell Fullerton, California
