Barry Schwartz wrote:
> Sidney Reilley II <[email protected]> skribis:
>> The following snippet is taken from Thomas W. Christopher's book,
>> "Icon Programming Language Handbook", page 36
>>
>> [quote]
>> The to operator associates to the left, e.g.,
>>
>> every writes(" ",1 to 2 to 3)
>> [/quote]
>>
>> I don't understand how the following produces:
>>
>> 12323
>>
>> I'm reading the above code as:
>>
>> write "each" integer 1 and 2 then "each" integer 2 and 3
>>
>> So I'm thinking the result should be:
>>
>> 1223
>>
>> but obviously I'm wrong, and I'm missing a piece of the puzzle.
>
> every writes(" ",(1 to 2) to 3)
>
> First tries (1 to 3) then tries (2 to 3), before failing, giving "1 2
> 3" followed by "2 3".
I got it! The generator (1 to 2) first returns 1, which becomes the
L.H.S of the "to 3" generator. After all the values are generated - 1
2 3 - "backtracking" occurs to get the next L.H.S. value, which in
turn is applied to the "to 3" generator. The values 2 3 are generated.
No more values? - Failure!!
Am I getting it?
> every writes(" ", 1 to (2 to 3))
>
> would try (1 to 2) and then (1 to 3), giving "1 2" followed by "1 2 3".
Same rationalization as above.
Thanks for explanation.
--
Sid
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