> Folks,
>
> I don't do much with co-expressions and was wondering, when you code x @
> ce, x gets transmitted to ce. But how does it arrive in ce?
>
> If I had something simple like
>
> ce := create i +:= 1
> i := 9
> i @ ce
>
> Then the i in ce is null. How is the i transmitted to ce?
>
> David
First activation, the transmitted value is discarded because there's nowhere
to receive it.
However if your co-expression activates another in a cooperating way:
procedure seq()
local n, i
i := 0
while (i +:= 1) do {
n := i @ &source
i := \n
}
end
procedure main()
local i, x, s
i := 0
x := 0
s := create seq()
while (i +:= 1) < 10 & x := (x + 10) @ s do
write(i, " ", x)
end
Here, I'm pumping the number returned + 10 back into the suspended coexp and
using it to bump the sequence forward. &source represents the coexp that
activated the ¤t one
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