ieumah marebutkeun paisan kosong atuh!!

--- amin mina <[EMAIL PROTECTED]> wrote:

> 
> tah duit anu Rp. 1.000,- deui mah ku jendran
> sudirman
> nya he2x (leres teu?)
> --- Edi Kusnadi <[EMAIL PROTECTED]> wrote:
> 
> > 
> > 
> > Gening harga embeteh 77.000.- lain 75.000. tah
> > timana anu 2 rebu
> > Pan pamuda ngumpulkeun 24.000 x 3 = 72.000
> > duit dibalikeun 1000 x 3 = 3000
> > di calo 2000
> > heg total jadi 77.000.-
> > kumaha tah jawabanana..... mun ieu kajawab anu
> > dihandap oge pasti kajawab
> > 
> > > > * aya 1 ekor embe hargana Rp 75.000
> > > > * aya 3 pamuda (Kang Irpan, Kang Ikmal, Kang
> MJ)
> > anu bade urunan meuli
> > eta
> > > > embe ...
> > > >
> > > > berarti masing2 pamuda eta ngumpulkeun @ Rp
> > 25.000... bener teu???
> > Akhirna
> > > > kakumpul Rp 75.000 sasuai harga jual... bener
> > teu???
> > > >
> > > > Tah... duit eta terus dipasihkeun ka calo embe
> > (Kang Agus Pakusarakan)
> > > > sajumlah duit eta = Rp75.000...
> > > > Masih bener teu??? Calo eta ternyata mikeun ka
> > padagangnya Rp 70.000
> > (Teh
> > > > Nia)
> > > > (dipotong komisi Rp. 5.000) Pasti dong???
> > > >
> > > > Terus duit 5.000 eta dibagikeun ka 3 pamuda
> tadi
> > @ Rp 1.000 jeung
> > sisanya Rp
> > > > 2.000
> > > > keur si calo... pasti masih bener pan???
> Didieui
> > permasalahanana!!!
> > > >
> > > > ...berarti masing2 pamuda ngantongan duit Rp
> > 1.000 (bener teu) atawa
> > jeung
> > > > kata
> > > > lain kuduna duit anu dikumpulkeun ku masing2
> > pamuda tadi Rp 25.000 -
> > > > Rp 1.000 = Rp 24.000. Berarti masing2 pamuda
> > kuduna mayar @ Rp 24.000
> > jadi
> > > > perhitungan matematika = 3 X Rp 24.000 = Rp
> > 72.000 bener dong???
> > > >
> > > > Lamun  ditotal Jendral Sudirmankeun  duit anu 
> > kakumpulkeun Rp.72.000
> > jeung
> > > > lamun ditambah Rp
> > > > 2.000 (bogana si calo) = Rp 74.000.
> > Pertanyaana???
> > > > KAMANA DUIT ANU Rp.1.000... HAYO...???
> > > >
> > > >
> > > >  JB
> > > >
> > 
> > 
> > 
> > 
> > 
> 
> 
> 
>               
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=====
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