I settled on Mark's shell script process to get IP address. I managed
to kludge together a case for Linux (Ubuntu Netbook) too. I did not
quite understand the matchtext line with its (?s) and (.*?)'s but the
Mac OSX case and Linux case almost worked without any changes.
The Linux shell is same as Mac's: ifconfig with either eth5 or wlan3
for interfaces.
The shell command results are:
wlan3 Link encap:Ethernet HWaddr 00:25:d3:7c:f2:49
inet addr:10.58.0.91 Bcast:10.58.0.255 Mask:255.255.255.0
The only difference between the two is there are the characters
"addr:" in front of the IP with no space too. The OSX shell has
spaces surrounding the IP.
Mark had mentioned that the (?s) represent spaces.
How does the matchText call know just to capture the IP address in the
variable retVal? It appears to look for "<space>inet<space>" and when
it finds it magically captures just the IP address that follows it????
How's it do that? Does matchText automatically get the first item/
word following the matched text??? Not quite sure how that works, but
it does :-)
--------------------snip----------------
break
case "Linux"
put shell("/sbin/ifconfig eth5") into
tEthernetConfig
put shell("/sbin/ifconfig wlan3") into
tWirelessConfig
set the itemdel to "."
--CHECK FOR ETHERNET CONNECTION
get matchText(tEthernetConfig,"(?s)inet (.*?)
",retVal)
if it is false then
-- CHECK FOR WIRELESS CONNECTION
get matchText(tWirelessConfig,"(?s)inet
(.*?) ",retVal)
if it is false then
return "0.0.0.0"
end if
end if
-- i have no clue how the matchtext works above but the
retVal is returns "addr:10.X.X.X". Sooo...
set the itemDel to ":"
put item 2 of retVal into cd fld "ipaddress"
end switch
return "0.0.0.0"
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