I'd tend to look for ways to do this with functions that work on whole collections and avoid loops.
If that is not found, or is hard to work with, I'd change the lists to be arrays. Each array is is keyed by parents. Each parent is an array of children. Children can be represented as an arrayed indexed by children. The elements of those might be ignored or have data. Loop on keys in LISTNEW... > On Aug 5, 2019, at 9:53 AM, Paul Dupuis via use-livecode > <use-livecode@lists.runrev.com> wrote: > > Today is not my coding day. I have a problem I should be able to design a > solution for an am struggling. Clearly I am missing "something" > > I have 2 lists (LISTNEW and LISTOLD) of the following format: > > ParentA > <space>Child 1 > <space>Child 2 > <space>etc. > ParentB > <space>Child 1 > <space>etc. > etc. > > The parents are in alphabetical sorted order, the children may not be in > sorted order > > I need to hunt through LISTOLD comparing the LISTOLD Parents to the LISTNEW > Parents > FOR any LISTOLD Parent present in LISTNEW, check the Children of the > matching Parents and add any Child for the LISTOLD Parent that is not already > under its matching LISTNEW Parent > FOR any LISTOLD Parent NOT in LISTNEW, I can ignore the Parent and its > Children > > I can not seem to write an approach to solve this today. Does any body have > some code so solve this they may be willing to share? > > _______________________________________________ > use-livecode mailing list > use-livecode@lists.runrev.com > Please visit this url to subscribe, unsubscribe and manage your subscription > preferences: > http://lists.runrev.com/mailman/listinfo/use-livecode > _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode
