Not sure what 'previous post' referred to. Reg ex "[0-9]+" (or equivalently
"\d+") would match one or more integers.
Provided this is the first/only instance of the pattern, I would have thought
that regex does provide the neatest solution, e.g.:
put "(" & iNewNumber ")" into tReplacement
put replaceText(tOldString , "\(\d+\)", tReplacement) into tNewString
On 26/04/2020 20:15, dunbarx--- via use-livecode wrote:
Pay no attention to the previous post, which only dealt with a single integer.
Sloppy.
THIS old fashioned method works, though:
on mouseUpput offset("(",yourString) into startCharput offset(")", yourString)
into endCharput random(999) into char (startChar + 1) to (endChar -1) of yourStringend mouseUp
Craig
-----Original Message-----
From: doc hawk via use-livecode <use-livecode@lists.runrev.com>
To: How to use LiveCode <use-livecode@lists.runrev.com>
Cc: doc hawk <doch...@gmail.com>
Sent: Sun, Apr 26, 2020 2:41 pm
Subject: Re: Wildcard? replaceText, offset?
On Apr 26, 2020, at 11:24 AM, Rick reasoned
In the middle-end part of the string I have “(x)” where x represents some
integer.
it could be (4) or (10) or (5) etc.
If you’re certain that this is the only, or even the first, integer, a regular
expression search and replace or [0-9]+ would do the trick.
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