Direct equivalent is probably
repeat with i = 0 to myArrayLength-1
put i-1 into j
if j < 0 then put myArrayLength-1 into j
.....
end repeat
OR, if you prefer a single-statement version
repeat with i = 0 to myArrayLength-1
put (i + myArrayLength-1) mod myArrayLength into j
.....
end repeat
OR - most efficient but risky - i.e. a bad choice iMHO :-)
put myArrayLength-1 into j
repeat with i = 0 to myArrayLength-1
.....
put i into j -- NB at the very end of the loop body
end repeat
This is risky in case you ever do a "next repeat" inside the loop body !!
Alex.
On 17/05/2022 07:35, jbv via use-livecode wrote:
Hi list,
What is the best and most efficient way to write the following
javascript loops in LC ?
for (let i = 0, j = myArray.length - 1; i < myArray.length; j = i++) {
}
This goes beyond simple nested loops.
So far, because of lack of time, I have pre-calculated the successive
values of i and j, and have put them into lists of words :
0 1 2 3 4 5
5 0 1 2 3 4
it remains fast enough for what I need to do, but there must be a more
elegant approach...
Thanks.
jbv
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