Sat, 30 Aug 2014 Geoff wrote :
> Used Alex's code to generate a list of the permutations of all the characters
> that were duplicates.
> Substituted in unique characters for each instance of the duplicates.
> Ran my permutation code on the rest of the characters, with the addition of
> the duplicates-permutation-strings as the base case.
I was working on the same line, but from the other end. I start with the
characters that are not duplicate and use your very fast code to get all the
permutations.
The I slot in, one for one, all the duplicate elements on all possible
positions. After slotting in each duplicate element, I delete duplicate lines,
so in the next run of inserting the next duplicate element, I will have to do
less, as the duplicate lines have been deleted. I am not completely finished
with the script & testing. I will post it as soon as possible.
I also tried to serialise Geoff's script and looked if I could get rid of
duplicates inside of the script. I did not manage as yet. But the serialised
script is a bit easier for me to play around with, as I can better watch the
different variables.
This is my serialised version of Geoff's original script :
function BC4_PermMech_Geoff_Serial_Chars N
put "01" & cr & "10"& cr into T
repeat with x = 2 to N
repeat with i = 0 to x
put T into T2
replace i with x in T2
replace cr with i & cr in T2
put T2 after R
end repeat
put R into T
put empty into R
end repeat
delete char -1 of T
return T
end BC4_PermMech_Geoff_Serial_Chars
All the best, Beat
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