Yes.

-Mark


> On Jul 27, 2016, at 12:48 PM, Richard Gaskin <[email protected]> 
> wrote:
> 
> Thanks, Mark.  You know I loves me some benchmarking. :)
> 
> Do all three produce the same result?
> 
> - rg
> 
> 
> Mark Talluto wrote:
> > Thought this might be interesting to those benchmarking reads on
> > arrays. I was working to optimize one small section of code in
> > our database and found that the method I figured would be the slowest
> > ended up being the fastest. Maybe this will be helpful to others
> > doing a lot of array work.
> >
> > Macbook Pro, macOS 10.11.5
> > LiveCode 8.1 dp2
> > Data: 135k records
> >
> >  (method 1) 1.36 seconds
> > --GET ALL THE RECORDS FROM THIS TABLE
> > repeat for each element xRecordClusterA in gCSIdatabaseA[xTableID]
> >     repeat for each element xElement in xRecordClusterA
> >             put xElement into tRecordA[xTableID][(the keys of 
> > xRecordClusterA)]
> >     end repeat
> > end repeat
> >
> >
> > (method 2) 220 ms
> > --GET ALL THE RECORDS FROM THIS TABLE
> > repeat for each element xRecord in gCSIdatabaseA[xTableID]
> >     repeat for each key xRecordID in xRecord
> >             put xRecord [xRecordID] into tRecordA[xTableID][xRecordID]
> >     end repeat
> > end repeat
> >
> >
> >  (method 3) 77 ms
> > --GET ALL THE RECORDS FROM THIS TABLE
> > repeat for each key xRecordCluster in gCSIdatabaseA[xTableID]
> >     put the keys of gCSIdatabaseA[xTableID][xRecordCluster] into tRecordID
> >     put gCSIdatabaseA[xTableID][xRecordCluster][tRecordID] into 
> > tRecordA[xTableID][tRecordID]
> > end repeat
> >
> 
> 
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