Actually, I think I meant tOS+2 to tOS+3, if the find starts on \x##, the the \ is tOS and tOS+1 is the x
That's way I get for rushing a reply. On 5/31/2018 4:47 PM, Bob Sneidar via use-livecode wrote: > You meant tOS+1 to tOS+2? > >> On May 31, 2018, at 13:39 , Paul Dupuis via use-livecode >> <use-livecode@lists.runrev.com> wrote: >> >> tOS+2 to tOS+2 into tByte1 and char tOS+6 to tOS+7 into byte2 to get the > > _______________________________________________ > use-livecode mailing list > use-livecode@lists.runrev.com > Please visit this url to subscribe, unsubscribe and manage your subscription > preferences: > http://lists.runrev.com/mailman/listinfo/use-livecode > _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode