Actually, I think I meant tOS+2 to tOS+3, if the find starts on \x##,
the the \ is tOS and tOS+1 is the x

That's way I get for rushing a reply.

On 5/31/2018 4:47 PM, Bob Sneidar via use-livecode wrote:
> You meant tOS+1 to tOS+2?
>
>> On May 31, 2018, at 13:39 , Paul Dupuis via use-livecode 
>> <use-livecode@lists.runrev.com> wrote:
>>
>> tOS+2 to tOS+2 into tByte1 and char tOS+6 to tOS+7 into byte2 to get the
>
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