Very helpful indeed !
Always learning :-) I did not know that a non-breaking space was
considered as a word !
Like St Thomas, I tried it and … you are right (of course ;-))
Yes, as you say, it is unlikely (mainly due to the fact that one use
two keys to type a non-breaking space)
but sure your function trim is a prudent precaution.
Thanks a lot Ken
André
Le 4 févr. 09 à 19:00, Ken Ray a écrit :
On 2/4/09 8:41 AM, "Andre.Bisseret" <andre.bisse...@inria.fr> wrote:
Hello
Thanks to all who paid attention to my question
Quite a nice number of ways (mainly variations around counting the
number of words)
BTW, just for 100% clairty, none of these "word-based" approaches
work if
there is a non-breaking space ( or  ) in the field.
Admittedly,
the possibility of this happening is extremely low, but to be on the
safe
side, this is "trim" function I use:
function trim what
if the platform is "MacOS" then
replace numToChar(202) with " " in what
else
replace numToChar(160) with " " in what
end if
return (word 1 to -1 of what)
end trim
So for testing an empty field, it would be:
if trim(fld 1) = "" then
HTH,
Ken Ray
Sons of Thunder Software, Inc.
Email: k...@sonsothunder.com
Web Site: http://www.sonsothunder.com/
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