Re: is among - problem

[Thomas J McGrath III]

AAWW, But Geoff, you cheated because NOW you know there are only 35 
possibles. At the beginning of this 'I' didn't know how many possible 
groups of three there would be.

But, I like your first solution and will play with it today to increase 
my understanding of transcript,

Thank you

Tom

On Nov 22, 2003, at 3:19 AM, Geoff Canyon wrote:

So the first question is, you have a list of three digit numbers, some 
of which are transposed copies of each other. You want to filter the 
list so that any transposed duplicates are removed. This should work:

  put empty into tNewList
  repeat for each line L in tList
    put sortChars(L) into tCandidate
    if tHitList[tCandidate] is not empty then next repeat
    put 1 into tHitList[tCandidate]
    put L & return after tNewList
  end repeat
function sortChars p
  put empty into r
  repeat for each char c in p
    put c & comma after r
  end repeat
  sort items of r
  replace comma with empty in r
  return r
end sortChars
On to the second problem, which is really the first since you wouldn't 
have the above problem to solve if you could generate the answer to 
the below directly. This code should do the trick. It produces a list 
of 35 three-digit numbers, which we'll verify as the right number:

on mouseUp
  put empty into tList
  repeat with i = 1 to 5
    repeat with j = i + 1 to 6
      repeat with k = j + 1 to 7
        put i & j & k & cr after tList
      end repeat
    end repeat
  end repeat
  put tList
end mouseUp
It's hard-coded, but for this case that isn't much of an issue. To 
verify that there are 35 solutions, consider that this problem 
translates to: choose three numbers from the set "1,2,3,4,5,6,7" To 
solve that, find 7C3, which is (7*6*5)/(3*2*1) That's 210/6, or 35

regards,

Geoff Canyon
[EMAIL PROTECTED]
On Nov 21, 2003, at 5:59 PM, Thomas J McGrath III wrote:

A group of three items from the list 1,2,3,4,5,6,7 with no duplicates 
in any order = 123 but no 213 or 312 or 231 or 321 and no doubles or 
triples = 111 or 112 or 323 or 322 etc. (WOW my daughter is only 13 
and this in my opinion is complex until I figured it out)
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Thomas J McGrath III      2003  [EMAIL PROTECTED]
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