The date formats only works over a short period of time, about 2^32 seconds (4 byte word). That is about 1934 to 2035. If you are using dates outside of that region then you need to work with dateItems and seconds. I think dateItems gives you the largest time span. To do this you have to convert your date to a dateItem with your own handler, not the convert function:

put "7/18/1868" into theDate
put myDateItemHandler(theDate) into theDate

function myDateItemHandler theDate
  get the itemDelimiter -- this get/set may not be needed
  set the itemDelimiter to "/"
  put item 1 of theDate into theMonth
  put item 2 of theDate into theDay
  put item 3 of theDate into theYear
  set the itemDelimiter to it-- this get/set may not be needed
  return theYear&comma&theMonth&comma&theDay&comma&comma&comma&comma
end myDateItemHandler

You can convert this dateItem to seconds and do your calculations. If you want to return a date convert your seconds to dateItems and write a handler which creates your desired date format.

Michael

On Jan 17, 2005, at 6:58 PM, Sarah Reichelt wrote:
What do I need to do to make the following work right? To get the centuries
right?


put "7/18/1868" into temp
  put temp into  fld 1
  convert temp to seconds
  put "  --  "&temp after fld 1
  convert temp to long date
  put "  --  "&temp after  fld 1

Hi Nelson,

The only way I could get it to work was to use Julian dates. if you go to my web page, you will see a DateTime library: "DateTime.rev.gz", which includes functions for translating dates to & from Julian format, originally written by Mark Weider.

Cheers,
Sarah
[EMAIL PROTECTED]
http://www.troz.net/Rev/

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