Hi,
Is the below flow correct for UML (TT mode)
1. UML process wants to execute a sys call say open().
2. UML TT comes to know this annuls with getpid(), and UML TT executes
open() on behalf of UML process.
3. UML process executes the getpid() and returns and signals TT.
4. By this time UML TT has finished executing the system call open and
has returned back, so TT fills in the registers of UML process.
5. Now UML process executes normally with the open file descriptor.
If the above steps are correct, then How does UML protects host kernel.
because even here TT will ask for host kernel services which may corrupt
host kernel ?
Is there any method by which it is prevented ?
Thanks a lot.
Abhi
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