hi,
先计算所有的 join 结果,结果中把相关的 join 字段带上, 再去基于 join 的结果去选择需要的结果是否可以? Best, Feng On Wed, Oct 16, 2024 at 10:42 AM 斗鱼 <1227581...@qq.com.invalid> wrote: > 大佬们,目前我遇到一个业务场景的问题, > 有如下四张表,其中一张事实表tableFact和三张维度表tableDimA、tableDimDetailB、tableDimDetailC进行left > join关联,这四张表根据userId、actPkId、bId、cType、create_time这几个参数进行关联,三张维度表通过actPkId进行关联 > > *目前需求是想实现根据维度表bId、cType、create_time这三个字段的数据的情况,动态转成对应join的SQL*,具体相关信息如下: > > *表结构大致信息:* > > tableFact( > userId String primary key, > create_time > ) > > tableDimA > ( > actPkId String primary key, > targetUserId String, > start_time datetime, > end_time datetime > > ) > > tableDimDetailB > ( > actPkId String primary key, > bId String > ) > > tableDimDetailC > ( > actPkId String primary key, > cType String > ) > > *假定:* > A: fact.userlddimA.targetUserld > B: fact.bId == dimB.bId > C: fact.cType == dimA.cType > D: fact.create time >= dimA.start time and fact.create time <= dimA.end > time > > *前置条件:*A必须存在,B、C、D可以组合存在,即B、C、D的所有可能组合条件存在, > > *举例如下参数情况:* > 如 (A B C)表示A、B、C的条件都存在的情况,组合出 > SELECT * > FROM tableFact P > LEFT JOIN tableDimA FOR SYSTEM_TIME AS OF P.proctime AS A ON P.userId = > A.targetUserId > LEFT JOIN tableDimDetailB FOR SYSTEM_TIME AS OF P.proctime AS B ON > A.actPkId = B.actPkId AND P.bId=B.bId > LEFT JOIN tableDimDetailC FOR SYSTEM_TIME AS OF P.proctime AS C ON > A.actPkId = C.actPkId AND P.cType=B.cType; > > 如 (A B C D)表示A、B、C D的条件都存在的情况,组合出如下查询语句 > SELECT * > FROM tableFact P > LEFT JOIN tableDimA FOR SYSTEM_TIME AS OF P.proctime AS A ON P.userId = > A.targetUserId > LEFT JOIN tableDimDetailB FOR SYSTEM_TIME AS OF P.proctime AS B ON > A.actPkId = B.actPkId AND P.bId=B.bId > LEFT JOIN tableDimDetailC FOR SYSTEM_TIME AS OF P.proctime AS C ON > A.actPkId = C.actPkId AND P.cType=B.cType > WHERE P.create_time BETWEEN A.start_time AND A.end_time; > > *表结构图信息* > > > > > 想请教下各位大佬,Flink或者有什么技术能实现这种动态多条件参数组合转成sql的实现方案吗?期待能收到各位大佬帮忙的指导回复,感谢 > > ------------------------------ > 斗鱼 > 1227581...@qq.com > > <https://wx.mail.qq.com/home/index?t=readmail_businesscard_midpage&nocheck=true&name=%E6%96%97%E9%B1%BC&icon=http%3A%2F%2Fthirdqq.qlogo.cn%2Fg%3Fb%3Dsdk%26k%3DYiaI7kvDORpPP1623Fzbtyg%26s%3D100%26t%3D525%3Frand%3D1641396237&mail=1227581167%40qq.com&code=> > >