You can re-use the GenericRecord object you used before and then just
re-serialize. If you've been given the byte array, then you can
deserialize to a GenericRecord using something similar to this:

reader = new GenericDatumReader<GenericRecord>(schema);

Decoder decoder = DecoderFactory.get().binaryDecoder(bytes, null);
GenericRecord record = reader.read(null, decoder);
record.put("user_id", 123456L);

-Joey

On Mon, Jan 12, 2015 at 5:21 PM, Check Peck <comptechge...@gmail.com> wrote:
> Yes that's what I am looking for. Question is - How do I update the
> GenericRecord, I want to update user_id field with some new random long
> number.?
>
> Can you provide an example how can I update GenericRecord and then serialize
> it to a new Byte Array?
>
> On Mon, Jan 12, 2015 at 4:34 PM, Joey Echeverria <j...@cloudera.com> wrote:
>>
>> I'm not sure I understand the question. You can certainly deserialize
>> the byte array back into a GenericRecord. You can then update that
>> GenericRecord and serialize that to a new byte array.
>>
>> Is that what you're looking for?
>>
>> -Joey
>>
>> On Mon, Jan 12, 2015 at 3:42 PM, Check Peck <comptechge...@gmail.com>
>> wrote:
>> > I have an Avro Schema which is like this -
>> >
>> >     {
>> >        "type":"record",
>> >        "name":"new_user",
>> >        "namespace":"com.hello",
>> >        "fields":[
>> >           {
>> >              "name":"user_id",
>> >              "type":[
>> >                 "long",
>> >                 "null"
>> >              ]
>> >           },
>> >           {
>> >              "name":"segment",
>> >              "type":[
>> >                 "string",
>> >                 "null"
>> >              ]
>> >           }
>> >        ]
>> >     }
>> >
>> > I am using my above Avro Schema like this to serialize the data and
>> > which
>> > gives me a Byte Array and works fine -
>> >
>> >     public static void main(String[] args) throws IOException {
>> >         Schema schema = new Parser()
>> >                 .parse("{ \"type\":\"record\", \"name\":\"new_user\",
>> > \"namespace\":\"com.hello\", \"fields\":[ { \"name\":\"user_id\",
>> > \"type\":[
>> > \"long\", \"null\" ] }, { \"name\":\"segment\", \"type\":[ \"string\",
>> > \"null\" ] } ] }");
>> >
>> >         byte[] originalAvrodata = getAvroBinaryData(schema);
>> >
>> >         // how to get newAvroData byte array in which user_id
>> >         // is change to some other random long number?
>> >     }
>> >
>> >     private static byte[] getAvroBinaryData(Schema schema) throws
>> > IOException {
>> >         GenericRecord record = new GenericData.Record(schema);
>> >         record.put("user_id", 123456L);
>> >         record.put("segment", "hello");
>> >
>> >         GenericDatumWriter<GenericRecord> writer = new
>> > GenericDatumWriter<GenericRecord>(schema);
>> >         ByteArrayOutputStream os = new ByteArrayOutputStream();
>> >
>> >         Encoder e = EncoderFactory.get().binaryEncoder(os, null);
>> >
>> >         writer.write(record, e);
>> >         e.flush();
>> >         byte[] byteData = os.toByteArray();
>> >         return byteData;
>> >     }
>> >
>> >
>> >
>> > I need to decode the `originalAvrodata` byte array and then change the
>> > `user_id` field value to some other `long` number and then construct a
>> > `newAvroData` byte array using the same schema which should have
>> > `user_id`
>> > field value to some random `long` number. Is this possible to do by any
>> > chance using Avro?
>>
>>
>>
>> --
>> Joey Echeverria
>
>



-- 
Joey Echeverria

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