Hi Robert, Thanks for reply !
Yes, I want a single pipeline instead of new job for every 30 seconds. In the approach you mentioned, it creates new job every time. Regards, Anjana ________________________________________ From: Robert Bradshaw [[email protected]] Sent: Monday, September 16, 2019 11:51 AM To: user Cc: Richard Amrith Lourdu Subject: Re: Looping in Dataflow(Creating multiple jobs for a while loop) You can put your pipeline definition inside your while loop, i.e. while True: to_date = time.time() p = beam.Pipeline(options=PipelineOptions()) (p | 'create surveys' >> beam.Create(id_list) | 'get data' >> beam.FlatMap(lambda id: get_api_data(id, from_date, to_date)) | 'send to output' >> beam.FlatMap(lambda input: (send_to_api(input))) ) from_date = to_date + timedelta(microseconds=1) time.sleep(30) p.run().wait_until_finish() which will run pipelines until your script terminates, but this will fire off a new batch job every 30+ seconds. It sounds like what you'd really want to do here is have a single streaming pipeline. On Mon, Sep 16, 2019 at 11:24 AM Juan Carlos Garcia <[email protected]> wrote: > > Hi Anjana, > > You need to separate your line of thoughts between the pipeline definition vs > what happens when you call *run* on the pipeline, given that you need > externalize the scheduling using something like a crontab, jenkins, or > another mechanism. > > Best regards, > JC > > On Mon, Sep 16, 2019 at 7:57 PM Anjana Pydi <[email protected]> > wrote: >> >> Hi, >> >> I am trying to run a task using an infinite while loop with change in input >> parameters as below but it creates a new job for every time. (I expect it to >> use same pipeline that is created before while loop and should be in a >> single job) >> >> p = beam.Pipeline(options=PipelineOptions()) >> >> while True: >> to_date = time.time() >> >> (p >> | 'create surveys' >> beam.Create(id_list) >> | 'get data' >> beam.FlatMap(lambda id: get_api_data(id, >> from_date, to_date)) >> | 'send to output' >> beam.FlatMap(lambda input: >> (send_to_api(input))) >> ) >> from_date = to_date + timedelta(microseconds=1) >> time.sleep(30) >> >> p.run().wait_until_finish() >> >> It works properly(in only one job) when there is no while loop as below: >> >> p = beam.Pipeline(options=PipelineOptions()) >> >> (p >> | 'create surveys' >> beam.Create(id_list) >> | 'get data' >> beam.FlatMap(lambda id: get_api_data(id, >> from_date, to_date)) >> | 'send to output' >> beam.FlatMap(lambda input: >> (send_to_api(input))) >> ) >> >> p.run().wait_until_finish() >> >> Could someone please suggest how to make the task run in same job instead of >> creating multiple jobs. >> >> Please let me know in case if any additional information needed. >> >> Thanks, >> Anjana >> >> >> ----------------------------------------------------------------------------------------------------------------------- >> The information contained in this communication is intended solely for the >> use of the individual or entity to whom it is addressed and others >> authorized to receive it. It may contain confidential or legally privileged >> information. If you are not the intended recipient you are hereby notified >> that any disclosure, copying, distribution or taking any action in reliance >> on the contents of this information is strictly prohibited and may be >> unlawful. If you are not the intended recipient, please notify us >> immediately by responding to this email and then delete it from your system. >> Bahwan Cybertek is neither liable for the proper and complete transmission >> of the information contained in this communication nor for any delay in its >> receipt. > > > > -- > > JC > ----------------------------------------------------------------------------------------------------------------------- The information contained in this communication is intended solely for the use of the individual or entity to whom it is addressed and others authorized to receive it. It may contain confidential or legally privileged information. If you are not the intended recipient you are hereby notified that any disclosure, copying, distribution or taking any action in reliance on the contents of this information is strictly prohibited and may be unlawful. If you are not the intended recipient, please notify us immediately by responding to this email and then delete it from your system. Bahwan Cybertek is neither liable for the proper and complete transmission of the information contained in this communication nor for any delay in its receipt.
