Then how i can generate correct time UUID key in java ?
8 квітня 2011 р. 22:58 Ed Anuff <e...@anuff.com> написав:
> Hmm, if you're really doing this, you're not getting a time uuid:
>
> UUID timeUUID = getTimeUUID().randomUUID();
>
> That call to randomUUID() is invoking the static randomUUID() method
> in java.util.UUID which is generating a non-time random uuid. I'm not
> sure why you're getting that error message though.
>
> Ed
>
> 2011/4/8 Олександр Силка <sylkaa...@gmail.com>:
> > Hi everyone,
> > I have column family called site sorted
> > by org.apache.cassandra.db.marshal.TimeUUIDType.
> > When I try to save some data using hector i get next
> > message InvalidRequestException(why:TimeUUID should be 16 or 0 bytes
> (3)).
> > My Cassandra version 0.7.0
> >
> > This is snippets of my code:
> > public static java.util.UUID getTimeUUID() {
> > return java.util.UUID.fromString(new com.eaio.uuid.UUID().toString());
> > }
> > UUID timeUUID = getTimeUUID().randomUUID();
> > List<HColumn<String, String>> columns = DaoHelper.getStringCols(site);
> > Mutator<UUID> mutator = HFactory.createMutator(keyspace,
> > UUIDSerializer.get());
> > for (HColumn<?, ?> column : columns) {
> > mutator.addInsertion(timeUUID, columnFamilyName, column);
> > }
> > I am new in Cassandra and i really want to understand how it works.So
> please
> > help me.
>
