Thanks. The above works. But when I try to use the binary values rather than the hex values, it does not work. i.e. instead of using 64ff, I use 01100100. Instead of 6Dff, I use 01101101. When using the binary values, everything (strings starting with a to z) seem to be going to n1 only. Any idea why ?
On Wed, Jul 6, 2011 at 11:18 AM, Richard Low <r...@acunu.com> wrote: > On Wed, Jul 6, 2011 at 3:06 PM, A J <s5a...@gmail.com> wrote: >> I wish to use the order preserving byte-ordered partitioner. How do I >> figure the initial token values based on the text key value. >> Say I wish to put all keys starting from a to d on N1. e to m on N2 >> and n to z on N3. What would be the initial_token values on each of >> the 3 nodes to accomplish this ? > > If all keys use characters a-z then the following will work: > > N1: 64ff > N2: 6dff > N3: 7aff > > (64, 6d and 7a are hex for ascii codes of d, m, z). Here the key (in > hex) 64ffff will go to N2 even though it starts with d. But every > string that starts with a-d with only characters a-z afterwards will > go to N1. > > Richard. > > -- > Richard Low > Acunu | http://www.acunu.com | @acunu >
