Hi, I am running cassandra version 1.2.19 and cqlsh version 3.1.8 in my setup
cqlsh:apprepo> select * from test_proxy_revisions_r21 limit 10 ; Traceback (most recent call last): File "./cqlsh", line 1039, in perform_statement_untraced self.cursor.execute(statement, decoder=decoder) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/cursor.py", line 81, in execute return self.process_execution_results(response, decoder=decoder) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/thrifteries.py", line 116, in process_execution_results self.get_metadata_info(self.result[0]) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/cursor.py", line 97, in get_metadata_info name, nbytes, vtype, ctype = self.get_column_metadata(colid) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/cursor.py", line 104, in get_column_metadata return self.decoder.decode_metadata_and_type(column_id) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/decoders.py", line 40, in decode_metadata_and_type valdtype = cqltypes.lookup_casstype(validator) File "./../lib/cql-internal-only-1.4.1.zip/cql-1.4.1/cql/cqltypes.py", line 145, in lookup_casstype raise ValueError("Don't know how to parse type string %r: %s" % (casstype, e)) ValueError: Don't know how to parse type string 'org.apache.cassandra.db.marshal.DynamicCompositeType(s=>org.apache.cassandra.db.marshal.UTF8Type)': weird characters '=>org.apache.cassandra.db.marshal.UTF8Type)' at end Any clue? Regards, Kaushal