In the case of PRIMARY KEY((organization_id, employee_id)), could I still do a query like Select ... where organization_id = x, to get all employees in a particular organization?
And, this will put all those employees in the same node, right? On Sun, Oct 9, 2016 at 9:17 AM, Graham Sanderson <gra...@vast.com> wrote: > Nomenclature is tricky, but PRIMARY KEY((organization_id, employee_id)) > will make organization_id, employee_id the partition key which equates > roughly to your latter sentence (I’m not sure about the 4 billion limit - > that may be the new actual limit, but probably not a good idea). > > On Oct 8, 2016, at 8:35 PM, Ali Akhtar <ali.rac...@gmail.com> wrote: > > the last '4 billion rows' should say '4 billion columns / cells' > > On Sun, Oct 9, 2016 at 6:34 AM, Ali Akhtar <ali.rac...@gmail.com> wrote: > >> Say I have the following primary key: >> PRIMARY KEY((organization_id, employee_id)) >> >> Will this create 1 row whose primary key is the organization id, but it >> has a 4 billion column / cell limit? >> >> Or will this create 1 row for each employee in the same organization, so >> if i have 5 employees, they will each have their own 5 rows, and each of >> those 5 rows will have their own 4 billion rows? >> >> Thank you. >> > > >
