Hi Jan,
there's no kind of magic, just annotate the class fields as:
@ObjectCreate.List(value = {
@ObjectCreate(pattern = "*/HTABLE"),
@ObjectCreate(pattern = "*/VTABLE"),
@ObjectCreate(pattern = "*/XTABLE")
})
public class Table {
@SetProperty // you can omit the 'attributeName' since it is the same
as in the attribute
private String name;
@SetProperty(attributeName = "x")
private Long posX;
@SetProperty(attributeName = "y")
private Long posY;
@BeanPropertySetter(pattern = "*/rows")
private Long rows;
}
please let us know if it works! :)
Alles Gute!
-Simo
http://people.apache.org/~simonetripodi/
http://twitter.com/simonetripodi
On Wed, Mar 5, 2014 at 11:55 AM, Jan Fröhlich
<jan.froehl...@infomotion.de>wrote:
> Hi all,
>
> given an XML with something like
> <REPORT>
> <XTABLE name="Table1" x="1200" y="2250">
> <rows>10</rows>
> </XTABLE>
> <VTABLE name="Table2" x="1400" y="2250">
> <rows>14</rows>
> </VTABLE>
> <HTABLE name="Table3" x="1600" y="2250">
> <rows>17</rows>
> </HTABLE>
> </REPORT>
>
> I would like to map all nodes (XTABLE, VTABLE and HTABLE) to one class
> Table and set the properties.
> While learning digester I created a class for each tag, but now I want to
> improve that.
>
> For the class itself the following should work
> @ObjectCreate.List(value = {
> @ObjectCreate(pattern = "*/HTABLE"),
> @ObjectCreate(pattern = "*/VTABLE"),
> @ObjectCreate(pattern = "*/XTABLE")
> })
> public class Table {
> private String name;
> private Long posX;
> private Long posY;
> private Long rows;
>
> }
>
> But how should I annotate the properties as I have to set the pattern
> attribute to all @SetProperty annotations and the pattern is different for
> all of them.
>
> Any help appreciated.
>
> Jan
>
