Thank you Aurelien, that works!

David Park   Software Developer

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On Wed, Jun 13, 2018 at 3:41 PM Aurélien Bénel <[email protected]>
wrote:

> Dear David,
>
> > I desire that value to be split out by base and bonus points.
>
> Then you’ll need an array as the key: a first member for the selection and
> a second one for the grouping.
>
>
> MAP :
>
> function(o) {
>    emit( [o.label, "base"] , o.basePoints);
>    emit( [o.label, "bonus"], o.bonusPoints);
> }
>
> REDUCE
>
> _sum
>
> QUERY
>
> ?group=true&startkey=["gold"]&endkey=["gold",{}]
>
>
> Regards,
>
> Aurélien
>
>
> > Début du message réexpédié :
> >
> > De: David Park <[email protected]>
> > Objet: Rép : couchdb erlang reduce - aggregate object
> > Date: 13 juin 2018 à 20:17:19 UTC+2
> > À: [email protected]
> > Répondre à: [email protected]
> >
> > ok. so here's my test
> >
> > 3 docs
> >
> > {"_id": "a", "label": "gold", "basePoints": 1000, "bonusPoints": 2000}
> > {"_id": "b", "label": "gold", "basePoints": 10000, "bonusPoints": 20000}
> > {"_id": "c", "label": "silver", "basePoints": 10000, "bonusPoints":
> 20000}
> >
> > Then I took your advice and wrote a javascript (not erlang) view
> >
> > function(o) {
> >    emit(o.label, o.basePoints);
> >    emit(o.label, o.bonusPoints);
> > }
> >
> > then threw in a reduce of
> >
> > _sum
> >
> > then I queried my view with group = true where key = label
> > And I get a response of
> > {
> >  "rows":[
> >    {"key":"gold","value":33000}
> >  ]
> > }
> >
> > I desire that value to be split out by base and bonus points.
> >
> > David Park   Software Developer
>

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