On Wed, Jul 22, 2015 at 4:51 PM, Jacques Nadeau <jacq...@dremio.com> wrote:
> SELECT > STRING_BINARY(CONVERT_TO(1, 'INT')) as i, > STRING_BINARY(CONVERT_TO(1, 'INT_BE')) as i_be, > STRING_BINARY(CONVERT_TO(1, 'BIGINT')) as l, > STRING_BINARY(CONVERT_TO(1, 'BIGINT')) as l_be, > STRING_BINARY(CONVERT_TO(1, 'INT_HADOOPV')) as l_be > from (VALUES (1)); > > -------------------+-------------------+-----------------------------------+-----------------------------------+--------+ > | i | i_be | l > | l_be | l_be0 | > > +-------------------+-------------------+-----------------------------------+-----------------------------------+--------+ > | \x01\x00\x00\x00 | \x00\x00\x00\x01 | \x01\x00\x00\x00\x00\x00\x00\x00 > | \x01\x00\x00\x00\x00\x00\x00\x00 | \x01 | > > +-------------------+-------------------+-----------------------------------+-----------------------------------+--------+ > > ... > > >select convert_to(x, 'INT') from (values 1000) tbl(x); > > The problem here is that Drill treats all number literals as BIGINT. > You're trying to convert to a four byte encoding. This doesn't work since > your input type requires eight bytes of precision. You either need to cast > to lower precision or change your encoding to BIGINT or some other large > precision encoding such as BIGINT_HADOOPV or BIGINT_BE. > So why does your convert_to(1,'int') work and my convert_to(x,'int') fail?
