You can only bind to a single Customer.
customer1: (Customer(grade==Grade.A) or Customer(grade==Grade.B))
cusomter2:Customer(code=="J")
why not do:
customer1: (Customer(grade==Grade.A, code=="J") or Customer(grade==Grade.B,
code=="J"))
Régis LOWE wrote:
Thanks for your reply,
(Customer(grade==Grade.A) or Customer(grade==Grade.B)) && Customer(code=="J")
works,
but it doesn't work with Bound Column :
customer: (Customer(grade==Grade.A) or Customer(grade==Grade.B)) && Customer(code=="J")
Mark Proctor <[EMAIL PROTECTED]> a écrit : the and isn't needed for top level
facts - so you can just write:
(Customer(grade==Grade.A) or Customer(grade==Grade.B))
Customer(code=="J")
The above should work,it should work even if you had t he && in there. Let me
know if its not.
Mark
Régis LOWE wrote:
Thanks Edson,
it works, but I fail to see why it's impossible to combine conditional
expressions
with drools.
Regis
Edson Tirelli a écrit :
Regis,
If Grade.A and Grade.B are object types, try this:
...
when
customer: Customer( code == "J", gr : grade -> ( gr.equals(Grade.A)
|| gr.equals(Grade.B) )
then
...
If Grade.A and Grade.B are primitive types:
...
when
customer: Customer( code == "J", gr : grade -> ( ( gr == Grade.A )
|| ( gr == Grade.B ) )
then
...
Hope it helps.
Edson
Régis LOWE wrote:
Hi,
can someone explain me how to write the following condition :
(Customer(grade==Grade.A) or Customer(grade==Grade.B)) and
Customer(code=="J")
the following snippet produces :
unknown:52:66 Unexpected token ')'
Unable to resolve ObjectType '('
rule "discount10"
no-loop true
when
#conditions
customer: (Customer(grade==Grade.A) or Customer(grade==Grade.B)) and
Customer(code=="J")
eval (customer.getTotal()>100000)
then
#actions
end
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