Bootstrapping spring context with spring-xml-location parameter

[Nikhil Chandrappa]

Hi All,

I am trying to start a cache server from gfsh with spring context
configuration file and I receive a exception saying,

java.io.FileNotFoundException: class path resource
[spring/context/spring-context.xml] cannot be opened because it does not
exist

Following is Start Server command

start server --name=server1 --server-port=0 --classpath=../target/
*Gemfire-JMS-Integration-0.0.1-SNAPSHOT.jar*:/Users/nchandrappa
/Documents/workspace/Gemfire-JMS-Integration/grid/lib/* --properties-file=
config/gemfire.properties --cache-xml-file=config/serverCache.xml
*--spring-xml-location=spring/context/spring-context.xml*
--initial-heap=100m --max-heap=100m

*Jar Structure*

Gemfire-JMS-Integration

src

 main

  - java

  - resources

  spring

  context

  spring-context.xml


*serverCache.xml*

<cache>

<pdx read-serialized="true" persistent="false"/>

<initializer>

    <class-name>
org.springframework.data.gemfire.support.SpringContextBootstrappingInitializer
</class-name>

    <parameter name="basePackages">

      <string>io.pivotal.gemfire.core,io.pivotal.jms.core</string>

    </parameter>

    </initializer>

</cache>


*gemfire.properties*

mcast-port=0

locators=localhost[10334]

log-level=config


please let me know, if I have missed any configurations in start server
command that I've mentioned above.

Thanks,

Nikhil
-- 

*Nikhil Chandrappa *| Data Engineer | New York

(315) 396 - 3789 | nchandra...@pivotal.io | Pivotal Software Inc.
<http://www.pivotal.io/>

server1.log
Description: Binary data