Hi Rene,

Yes, bash complains about the structure of the command... I tried so many
variations until I found the explanation:

"You are getting that error because you are telling bash to interpret
/usr/bin/svn. Since /usr/bin/svn is a binary file and not a bash script,
bash is giving you that error."
(http://unix.derkeiler.com/Newsgroups/comp.unix.programmer/2008-12/msg00221.html)

Thanks anyway!

Marcello



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