when I use 'hive --service llap --name llap_service --size 4g --cache 4g' to
generate the startup script for llap, an exception throws:
java.lang.IllegalArgumentException: Cache size (4.00GB) has to be smaller than
the container sizing (4.00GB)
at
com.google.common.base.Preconditions.checkArgument(Preconditions.java:92)
at
org.apache.hadoop.hive.llap.cli.LlapServiceDriver.run(LlapServiceDriver.java:207)
at
org.apache.hadoop.hive.llap.cli.LlapServiceDriver.main(LlapServiceDriver.java:104)
is there any reasons why should follow this rule?
Thanks
Zhihua Deng