Have you tried to run the provided examples? that is a excellent way to
figure out this kind of configuration problems.

regards


2013/4/15 Kendall Shaw <[email protected]>

> How can I associate a steps class with a story? It would be great if I
> could somehow indicate: use this class with this story.
>
> So far, all of my attempts have resulted in no stories being found.
>
> From main:
>
>         Embedder emb = new Embedder();
>         List<String> stories = Arrays.asList("stories/test_**
> steps.story");
>         emb.candidateSteps().add(new TestSteps());
>         emb.runStoriesAsPaths(stories)**;
>
> stories/test_steps.story:
>
> Story: A story
>
> Scenario: A something and something else
>
> Given a something
> Then something else
>
>
> public class TestSteps extends Steps {
>
>     @Given("a something")
>     public void givenASomething() {
>         System.out.println("**givenASomething()");
>     }
>
>     @Then("something else")
>     public void somethingElse() {
>         System.out.println("**somethingElse()");
>     }
> }
>
> the result is:
>
> Exception in thread "main" org.jbehave.core.io.**StoryResourceNotFound:
> Story path 'stories/test_steps.story' not found by class loader
> sun.misc.Launcher$**AppClassLoader@4c5a9c6e
>
> "stories" is on the classpath. I've also copied code from the
> AnnotatedEmbedder class from the documentation. The part:
>
>  new StoryFinder().findPaths(**CodeLocations.**
> codeLocationFromPath(getClass(**)), "**/*.story", "");
>
> finds the story (I copied it into the source directory).
>
> The result is that the test completes with 0 steps and 0 stories.
>
> Is there some part that I am missing?
>
> Kendall
>
> --
> ThisIsHardToRead, asIsThis. This_is_easier, unless_it_is_underlined.
> This.is.easy. This-is-easy-too. Almost as easy to read as this.
>
>
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