Hi,
I'm not sure about your configuration, particularly about the log file that was
read once..
It would be nice to have some more details about that.
However, you should be aware that, if your system system under test cannot bear 15 TPS, the whole test will be slower thus returning
less transaction in 6 hours.
So, in this case, the Constant Throughput Timer, cannot make your system faster.
You can check if this is the case, just by lowering the load (e.g to 5 tps) and adjust your math: you should discover that the
numbers are ok.
regards
Il 15/05/2012 14:59, Deepak Goel ha scritto:
Hey
Is there a possibility that:
Each transaction of yours in the access log contains more hits to the server.
i.e: HTML page has gifs too..
:)
Deepak
On 5/15/12, James Musselwhite<james.musselwh...@gmail.com> wrote:
When I say "was read once", I was assuming that the Access Log Sampler will
only parse the access log one time, even if the throughput shaper has more
requests than is available in the access log. My access log had 194k
entries, but my shaper was set for 15dps for 6 hours, which is more than
194k requests. Would it start the log over again or would it just end at
194k?
On Mon, May 14, 2012 at 1:25 PM, Deepak Goel<deic...@gmail.com> wrote:
Hey
Some possibilities
1. Network Issue rejecting connections resulting in errors also being
registered in the results log
2. The hardware machine rejecting connection due to overload
I am unsure what do you mean by : "194K entries because the
access log was only read once"
:)
Deepak
On 5/14/12, James Musselwhite<james.musselwh...@gmail.com> wrote:
Hi folks
I've got an access log with 194K requests
I ran a test with the throughput shaping timer at 15 RPS for 6 hours,
which
should be 324K requests
My results log has 235K entries
I would expect my results log to have either a.) 194K entries because
the
access log was only read once or b.) 324K entries because it just kept
reading the same log over and over to fulfill the demands of the
throughput
shaping timer.
However, my result log is 235K which doesn't mean anything to me. Can
someone elucidate how this works?
Thanks!
James
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