2010/5/24 Peter Neubauer <peter.neuba...@neotechnology.com>:
> Thomas,
> sorry for taking so long to answer. Welcome to Neo4j!
>
> On Fri, May 21, 2010 at 10:37 PM, Thomas Sant'ana <maill...@gmail.com> wrote:
>> 1)  In the Matrix example (I saw it in several videos), what whould be the
>> proper way to query: "All people that Neo knows and love him?' In this case
>> it's a single hops, so I think the way is to iterate through all "love"
>> relations and see if the come back to Neo. But if we have more hops would we
>> need to have a traversal in a traversal?
> In this case, one approach would be to go along the KNOWS
> relationships of Neo (probably later in several hops) and check if
> there is an outgoing LOVES relationship back to Neo, something like
> http://gist.github.com/411695 (where Trinity doesn't know Neo so we go
> 2 KNOWS hops deep.
>
>
>>
>> 2) Is there a simple way to know how many edges/relation of a certain type
>> come out of a node? I figure I can iterate throw the relations, but I was
>> thinking of using this to choose the cheapest starting node for a traversal.
> Not really, since there are no global measures stored per se and
> almost all data is loaded lazy. However, if you want that, you could
> store the number of relationships when you operate on that node in an
> index (e.g. Lucene). Who useful that is regarding update performance
> and keeping things in sync depends on your usecase.
Or you could store that number on the node directly, which to me seems
like a better place.
>
>>
>> 3) Let say I have a Car graph, with:
>>
>> ReferenceNode (RN) --> Cars
>> RN --->  Manufactures --> Ford / GM/ SAAB/ Volvo etc.
>> RN --->  Colors ---> Grey, Silver, ....
>> RN ---> MakeYear ---> 2000, 2001, 2002
>>
>> A given car has a relaction to a Manufactures, Color, and Make year:
>>
>> Cars ---> aCar
>> aCar --> Silver
>> aCar ---> 2000
>> aCar ---> SAAB
>>
>> How can I get all the 2000 - 2001, Silver, SAAB?
>
> I have made the basic structure in http://gist.github.com/411699 .
> Now, the question is about how best to optimize set operations between
> the different criteria. You could start at the year_2000 node (finding
> it with an index lookup for the year 2000, to be added to the code) as
> I did and iterate through all car nodes, and return everything that
> has a COLOR connection to the Silver node, and a MANUFACTURER
> connection to SAAB. However, having multiple years, you even could add
> an index on top of e.g. the year nodes in order to be able to
> effectively select multiple years. Do you have some more info on the
> dataset sizes of your domain so I can flesh the GIST out a bit with
> your search?
>
> /peter
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-- 
Mattias Persson, [matt...@neotechnology.com]
Hacker, Neo Technology
www.neotechnology.com
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