With cypher you can do: start a=(10) match a-[:FOLLOW]->b-[:FOLLOW]->a return a
where 10 can be your node Id or you can either use an index. Cheers. 2011/9/20 iamyuanlong <yuanlong1...@gmail.com> > hi all, > I have some relation like this: > > http://neo4j-community-discussions.438527.n3.nabble.com/file/n3352328/follow.jpg > > what should I do to get the users who has been B Followed and has Followed > back to B. > In the image the result should be (A). > > -- > View this message in context: > http://neo4j-community-discussions.438527.n3.nabble.com/Neo4j-how-to-get-the-User-who-has-been-B-Followed-who-has-Followed-Back-tp3352328p3352328.html > Sent from the Neo4j Community Discussions mailing list archive at > Nabble.com. > _______________________________________________ > Neo4j mailing list > User@lists.neo4j.org > https://lists.neo4j.org/mailman/listinfo/user > -- Adriano Almeida Caelum | Ensino e Inovação www.caelum.com.br _______________________________________________ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user
