Chris, thanks again for your replies.
I realize now that I don't have the 'getConfig' method -- I'm writing a server 
plugin and I only get the GraphDatabaseService interface passed to my method, 
not a EmbeddedGraphDatabase. Is there an equivalent way of getting the highest 
node index through the interface?
Thanks.

> Date: Thu, 10 Nov 2011 12:01:31 +0200
> From: chris.gio...@neotechnology.com
> To: user@lists.neo4j.org
> Subject: Re: [Neo4j] Sampling a Neo4j instance?
> 
> Answers inline.
> 
> 2011/11/9 Anders Lindström <andli...@hotmail.com>:
> >
> > Thanks to the both of you. I am very grateful that you took your time to 
> > put this into code -- how's that for community!
> > I presume this way of getting 'highId' is constant in time? It looks rather 
> > messy though -- is it really the most straightforward way to do it?
> 
> This is the safest way to do it, that takes into consideration crashes
> and HA cluster membership.
> 
> Another way to do it is
> 
> long highId = db.getConfig().getIdGeneratorFactory().get( IdType.NODE
> ).getHighId();
> 
> which can return the same value with the first, if some conditions are
> met. It is shorter and cast-free but i'd still use the first way.
> 
> getHighId() is a constant time operation for both ways described - it
> is just a field access, with an additional long comparison for the
> first case.
> 
> > I am thinking about how efficient this will be. As I understand it, the 
> > "sampling misses" come from deleted nodes that once was there. But if I 
> > remember correctly, Neo4j tries to reuse these unused node indices when new 
> > nodes are added. But is an unused node index _guaranteed_ to be used given 
> > that there is one, or could inserting another node result in increasing 
> > 'highId' even though some indices below it are not used?
> 
> During the lifetime of a Neo4j instance there is no id reuse for Nodes
> and Relationships - deleted ids are saved however and will be reused
> the next time Neo4j starts. This means that if during run A you
> deleted nodes 3 and 5, the first two nodes returned by createNode() on
> the next run will have ids 3 and 5 - so highId will not change.
> Additionally, during run A, after deleting nodes 3 and 5, no new nodes
> would have the id 3 or 5. A crash (or improper shutdown) of the
> database will break this however, since the ids-to-recycle will
> probably not make it to disk.
> 
> So, in short, it is guaranteed that ids *won't* be reused in the same
> run but not guaranteed to be reused between runs.
> 
> > My conclusion is that the "sampling misses" will increase with index usage 
> > sparseness and that we will have a high rate of "sampling misses" when we 
> > had many deletes and few insertions recently. Would you agree?
> 
> Yes, that is true, especially given the cost of the "wasted" I/O and
> of handling the exception. However, this cost can go down
> significantly if you keep a hash set for the ids of nodes you have
> deleted and check that before asking for the node by id, instead of
> catching an exception. Persisting that between runs would move you
> away from encapsulated Neo4j constructs and would also be more
> efficient.
> 
> > Thanks again.
> > Regards,Anders
> >
> >> Date: Wed, 9 Nov 2011 19:30:36 +0200
> >> From: chris.gio...@neotechnology.com
> >> To: user@lists.neo4j.org
> >> Subject: Re: [Neo4j] Sampling a Neo4j instance?
> >>
> >> Hi,
> >>
> >> Backing Jim's algorithm with some code:
> >>
> >>     public static void main( String[] args )
> >>     {
> >>         long SAMPLE_SIZE = 10000;
> >>         EmbeddedGraphDatabase db = new EmbeddedGraphDatabase(
> >>                 "path/to/db/" );
> >>         // Determine the highest possible id for the node store
> >>         long highId = ( (NeoStoreXaDataSource)
> >> db.getConfig().getTxModule().getXaDataSourceManager().getXaDataSource(
> >>                 Config.DEFAULT_DATA_SOURCE_NAME )
> >> ).getNeoStore().getNodeStore().getHighId();
> >>         System.out.println( highId + " is the highest id" );
> >>         long i = 0;
> >>         long nextId;
> >>
> >>         // Do the sampling
> >>         Random random = new Random();
> >>         while ( i < SAMPLE_SIZE )
> >>         {
> >>             nextId = Math.abs( random.nextLong() ) % highId;
> >>             try
> >>             {
> >>                 db.getNodeById( nextId );
> >>                 i++;
> >>                 System.out.println( "id " + nextId + " is there" );
> >>             }
> >>             catch ( NotFoundException e )
> >>             {
> >>                 // NotFoundException is thrown when the node asked is not 
> >> in use
> >>                 System.out.println( "id " + nextId + " not in use" );
> >>             }
> >>         }
> >>         db.shutdown();
> >>     }
> >>
> >> Like already mentioned, this will be slow. Random jumps around the
> >> graph are not something caches can keep up with - unless your whole db
> >> fits in memory. But accessing random pieces of an on-disk file cannot
> >> be done much faster.
> >>
> >> cheers,
> >> CG
> >>
> >> On Wed, Nov 9, 2011 at 6:08 PM, Jim Webber <j...@neotechnology.com> wrote:
> >> > Hi Anders,
> >> >
> >> > When you do getAllNodes, you're getting back an iterable so as you point 
> >> > out the sample isn't random (unless it was written randomly to disk). If 
> >> > you're prepared to take a scattergun approach and tolerate being 
> >> > disk-bound, then you can ask for getNodeById using a made-up ID and deal 
> >> > with the times when your ID's don't resolve.
> >> >
> >> > It'll be slow (since the chances of having the nodes in cache are low) 
> >> > but as random as your random ID generator.
> >> >
> >> > Jim
> >> > _______________________________________________
> >> > Neo4j mailing list
> >> > User@lists.neo4j.org
> >> > https://lists.neo4j.org/mailman/listinfo/user
> >> >
> >> _______________________________________________
> >> Neo4j mailing list
> >> User@lists.neo4j.org
> >> https://lists.neo4j.org/mailman/listinfo/user
> >
> > _______________________________________________
> > Neo4j mailing list
> > User@lists.neo4j.org
> > https://lists.neo4j.org/mailman/listinfo/user
> >
> _______________________________________________
> Neo4j mailing list
> User@lists.neo4j.org
> https://lists.neo4j.org/mailman/listinfo/user
                                          
_______________________________________________
Neo4j mailing list
User@lists.neo4j.org
https://lists.neo4j.org/mailman/listinfo/user

Reply via email to