Argh...
Make that
c - n \cdot p
It always helps to check that points on a line are zero distance from the
line.
On Fri, Oct 14, 2011 at 9:57 AM, Ted Dunning <ted.dunn...@gmail.com> wrote:
> This form is equivalent to a dot product:
>
> n \cdot x = c
>
> where n is the normalized vector n = (A, B, ...) / | (A, B, ...) |, x is
> the vector form of the point and c = Z / | n |
>
> The vector n is unit length and orthogonal to the line and c is the
> shortest distance to the origin.
>
> The distance from point p to the line is just
>
> n \cdot p + c
>
>
> On Fri, Oct 14, 2011 at 12:37 AM, Sean Owen <sro...@gmail.com> wrote:
>
>> I forget what the answer is for the Ax + By + ... = Z form; I should
>> really look it up. I missed that day in 6th grade or something.
>>
>
>
