Yeah... right now you have the full cross product, but one side only has one element so the product is trivial.
It isn't that much worse if that side has a few elements. On Sat, Dec 8, 2012 at 9:49 PM, Marty Kube < martyk...@beavercreekconsulting.com> wrote: > #2 Might be a nice general approach. The trick is that you need the full > cross product of feature vectors and trees. I am going to give that some > thought about how to do the join and the map reduce pipeline. >
